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  <front>
    <article-meta>
      <title-group>
        <article-title>Advancing Critical Force Determination in Reinforced Concrete Columns: A Practical Approach</article-title>
        <subtitle>Memajukan Penentuan Gaya Kritis pada Kolom Beton Bertulang: Sebuah Pendekatan Praktis</subtitle>
      </title-group>
      <contrib-group content-type="author">
        <contrib id="person-5ee49a8eb4bdf70fa15c8994813b7b6c" contrib-type="person" equal-contrib="no" corresp="no" deceased="no">
          <name>
            <surname>Abduganiyevna</surname>
            <given-names>Kulmirzayeva Gulrabo</given-names>
          </name>
          <email>gkulmirzayeva@mail.ru</email>
          <xref ref-type="aff" rid="aff-1" />
        </contrib>
        <contrib id="person-46e6dc5cd5802a8c3065ceb98abcc15f" contrib-type="person" equal-contrib="no" corresp="no" deceased="no">
          <name>
            <surname>Kosimovich</surname>
            <given-names>Kosimov Turaboy</given-names>
          </name>
          <email>gkulmirzayeva@mail.ru</email>
          <xref ref-type="aff" rid="aff-2" />
        </contrib>
      </contrib-group>
      <aff id="aff-1">
        <country>Uzbekistan</country>
      </aff>
      <aff id="aff-2">
        <country>Uzbekistan</country>
      </aff>
      <history>
        <date date-type="received" iso-8601-date="2024-03-25">
          <day>25</day>
          <month>03</month>
          <year>2024</year>
        </date>
      </history>
      <abstract />
    </article-meta>
  </front>
  <body id="body">
    <sec id="heading-ad963a4f2577b6e5881e5890aa85dcc7">
      <title>
        <bold id="_bold-11">Introduction</bold>
      </title>
      <p id="paragraph-f74b2733743cde41a94406d8ca4a301c">It is important to take into account the age of the concrete and the load shoulder and time of loading and the limit value of the amount of critical force in ensuring the priority of columns made of reinforced concrete acting in eccentric compression. The superiority of a reinforced concrete column depends on the amount of high critical force applied to it [1].</p>
    </sec>
    <sec id="heading-ca5ebe3927aca89af2c7a0dfe9e98946">
      <title>
        <bold id="_bold-13">Methods</bold>
      </title>
      <p id="_paragraph-16">In the current normative rules, the calculation of the deformation due to the longitudinal force is not required in cases where the elements acting on eccentric compression are elastic [2]. However, in many cases, the longitudinal bending of reinforced concrete columns subjected to eccentric compression increases from the amount of bending moment at the loaded shoulder to the amount of bending moment resulting from longitudinal bending. Column priority according to the applicable standard provided when available.</p>
      <fig id="figure-panel-a329b23e65cc3f02bb7865dbaec01634">
        <label>Figure 1</label>
        <caption>
          <p id="paragraph-4382b239bc9445cd5da523d1becd9989" />
        </caption>
        <graphic id="graphic-1a0e79e684dcd4ca340667a471d87099" mimetype="image" mime-subtype="jpeg" xlink:href="r1.jpg" />
      </fig>
      <p id="_paragraph-18">while, the structural structure of column concrete changes and the slip property increases. Therefore, it is important to determine the critical strength of reinforced concrete columns.</p>
      <fig id="figure-panel-7c1922727e7d7ffb56eeeae378c91fb8">
        <label>Figure 2</label>
        <caption>
          <title>Report and structural schemes of reinforced concrete columns operating in non-central compression: a) the cross – sectional surface of the column is in full compression; b) the case where ¼ of the upper cross – sectional surface is compressed; c) the case where ¾ of the cross – sectional surface of the column works in compression.</title>
          <p id="paragraph-5124baa4eaf4d3c796e6182bfa78c252" />
        </caption>
        <graphic id="graphic-9e530e91b0ce26e98072521d3cf7ee81" mimetype="image" mime-subtype="png" xlink:href="1a.png" />
      </fig>
      <fig id="figure-panel-2487e81fcdd49a3faaa63c7e16420d96">
        <label>Figure 3</label>
        <caption>
          <title>Report and structural schemes of reinforced concrete columns operating in non-central compression: a) the cross – sectional surface of the column is in full compression; b) the case where ¼ of the upper cross – sectional surface is compressed; c) the case where ¾ of the cross – sectional surface of the column works in compression.</title>
          <p id="paragraph-5625763f3bab956829de2779e79fff2f" />
        </caption>
        <graphic id="graphic-9733cd778c987f5defb5e0a9a101914c" mimetype="image" mime-subtype="jpeg" xlink:href="1b.jpg" />
      </fig>
      <fig id="figure-panel-dcef71cc92c8d9746386e2e81c7004dc">
        <label>Figure 4</label>
        <caption>
          <title>Report and structural schemes of reinforced concrete columns operating in non-central compression: a) the cross – sectional surface of the column is in full compression; b) the case where ¼ of the upper cross – sectional surface is compressed; c) the case where ¾ of the cross – sectional surface of the column works in compression.</title>
          <p id="paragraph-3fab68187bc3555dd4fe779962de3ec1" />
        </caption>
        <graphic id="graphic-86deba6e0cbbcabfa0c0909efbafeb1d" mimetype="image" mime-subtype="png" xlink:href="1c.png" />
      </fig>
      <fig id="figure-panel-361685582c4c42c474402c91af70a9e5">
        <label>Figure 5</label>
        <caption>
          <title>Report and structural schemes of reinforced concrete columns operating in non-central compression: a) the cross – sectional surface of the column is in full compression; b) the case where ¼ of the upper cross – sectional surface is compressed; c) the case where ¾ of the cross – sectional surface of the column works in compression.</title>
          <p id="paragraph-23b2161140a4f0899c6f4ade4154af80" />
        </caption>
        <graphic id="graphic-80459882d4787d7cec092915fffe5b96" mimetype="image" mime-subtype="png" xlink:href="1d.png" />
      </fig>
    </sec>
    <sec id="heading-fb71fd9ce5c8646c11c3aeffe0e7d508">
      <title>
        <bold id="_bold-14">Results and Discussions</bold>
      </title>
      <p id="paragraph-65b0ff3c2993d22c216d2d6354c01442">Determination of the critical force of a reinforced concrete column with a rectangular cross-sectional surface subjected to centrifugal compression.</p>
      <p id="_paragraph-21">
        <bold id="bold-9a1c41d53a054f2c620b9d1084e25ead">a.</bold>
        <bold id="_bold-15">Given</bold>
      </p>
      <p id="paragraph-18678a0597cdc3121f2b343efe3dc449">The dimensions of the cross-sectional surface of the column b = 15 sm, h = 24 sm, a = 2 sm. Column concrete grade is B30, dried under natural conditions. B(28) = 30 MPa = 30; value of conical subsidence is 3-4sm; the column is symmetrical in shape 4F20AIII (75; equipped with class armature; the calculated length of the column is the load falling on the transverse surface of the column, acting from the center of gravity along the shoulder, the relative humidity of the outside air during operation of the column is W=75% [3].</p>
      <fig id="figure-panel-03058348c9bf05ccc9d881a2a2b5a16d">
        <label>Figure 6</label>
        <caption>
          <p id="paragraph-405559d6fcdcac4c3e197cea0abfbebe" />
        </caption>
        <graphic id="graphic-aa7f6d4760b63c569dabe1576d889ab1" mimetype="image" mime-subtype="jpeg" xlink:href="r2.jpg" />
      </fig>
      <p id="_paragraph-22">
        <bold id="bold-748aa7f7fcf6eaaba71d7c37e250a1c4">b.</bold>
        <bold id="_bold-16">Objective</bold>
      </p>
      <p id="paragraph-15da523072c040af0fc5897772fe1a8a">The column is loaded at full age and is required to determine the continuous critical force with respect to the moment of time</p>
      <fig id="figure-panel-8d4597ddf00f81c78c86eecb614242c9">
        <label>Figure 7</label>
        <caption>
          <p id="paragraph-b23dbb07c0e1ffade6d647d3f9adca0d" />
        </caption>
        <graphic id="graphic-fd38096b2e6f000d86043336504163fb" mimetype="image" mime-subtype="jpeg" xlink:href="r3.jpg" />
      </fig>
      <p id="_paragraph-23">
        <bold id="bold-23d122e531c18d4a22a7c1d1fe2f321d">c. Solution</bold>
      </p>
      <p id="paragraph-dfa888f3efd211ec0855be037b03ae66">The open surface modulus of the column is determined as follows [4].</p>
      <p id="_paragraph-24">The working height of the section surface affected by the bending moment is equal to the following value:</p>
      <p id="paragraph-5b7cf44d5ceb0e1db1f66159d83e2fad">
        <inline-formula id="inline-formula-8830d113192815981663e78b2450cfc7" content-type="math/tex">
          <tex-math><![CDATA[h_0=h-a=0,15-0,02=0,13m=13 sm]]></tex-math>
        </inline-formula>
      </p>
      <p id="_paragraph-25">1. we can determine the strength of concrete with age from the table. From this.</p>
      <p id="paragraph-791662892e29368b1f1fbb69562020fc">
        <inline-formula id="inline-formula-0315f5ed881d1b06e34f78c2c69e57f8" content-type="math/tex">
          <tex-math><![CDATA[t_0=60 sutka  t→∞     R_b^G (60)=33,9 МПa ; R_b^G (∞)=39,1 МПa]]></tex-math>
        </inline-formula>
      </p>
      <p id="_paragraph-26">From table 2, we determine the modulus of elasticity of concrete according to the above values.<inline-formula id="inline-formula-a9ceb00fb922ee88cb369771f424c351" content-type="math/tex"><tex-math><![CDATA[E_b (60)=33,87∙10^3 МПa=3,387∙10^10 H/m^2]]></tex-math></inline-formula></p>
      <p id="paragraph-422c0b3219afab9b09bedfb8953f0c5e">
        <inline-formula id="inline-formula-53dde1adabbe786d832ce06a40334b9a" content-type="math/tex">
          <tex-math><![CDATA[E_b (∞)=35,69∙10^3 МПa=3,56∙10^10 〖H/m〗^2]]></tex-math>
        </inline-formula>
      </p>
      <p id="_paragraph-27">From tables 11 and 12, we determine the values ​​​​of the indicators of the continuous deformation function of concrete:</p>
      <p id="paragraph-5cc359a37c68f729a74299aec9a5e47a">
        <inline-formula id="inline-formula-cf02e5ec81dfd70cd3ab1f8f4e992ad9" content-type="math/tex">
          <tex-math><![CDATA[γ=0,012 sut^(-1);    γ_1=0,006sut^(-1);   c=0,50;  d=0,7.]]></tex-math>
        </inline-formula>
      </p>
      <p id="paragraph-fa45f7295faff564df6624eeb25615ef">Based on these equations, we define the following functions.</p>
      <p id="paragraph-b9f9b69450ad362e35724ed4fdd1d0a9">
        <inline-formula id="inline-formula-cd81b1ae522295bceac7197a4404d89b" content-type="math/tex">
          <tex-math><![CDATA[Ω(t_0 )=C+de^(-γt_0 )=Ω(60)=C+de^(-γ60)=0,5+0,7e^(-0,012∙60)=0,841;]]></tex-math>
        </inline-formula>
      </p>
      <p id="paragraph-d947118f70fcf0fad0c8a545a045bb56">
        <inline-formula id="inline-formula-c6c32545987a7d52ad12568ca3a0a448" content-type="math/tex">
          <tex-math><![CDATA[f(t-t_0 )=1-ke^(-γ(t-t_0))=f(∞-60)=1-ke^(-γ_1 (∞-60))=]]></tex-math>
        </inline-formula>
      </p>
      <p id="paragraph-2d3a5d38eeb7f65491db8e24d19b8346">
        <inline-formula id="inline-formula-20522493bc4a8c91da18718ffba4585c" content-type="math/tex">
          <tex-math><![CDATA[=1-0,8∙e^(-0,006(∞-60))=1,0]]></tex-math>
        </inline-formula>
      </p>
      <p id="_paragraph-29">2. from the table</p>
      <p id="_paragraph-32">
        <inline-formula id="inline-formula-d37a096c8783a7abcf2f5991379cf2c5" content-type="math/tex">
          <tex-math><![CDATA[C^N=(∞,28)=79∙10^(-6) МПa^(-1)=7,9∙10^(-11) m^2/H,]]></tex-math>
        </inline-formula>
      </p>
      <p id="paragraph-370dbf913b05204ef350f8ef4dd3da12">we select values ​​from table 6 and table 7. <inline-formula id="inline-formula-3ea6c6606d11a8b742565a08d247d2bf" content-type="math/tex"><tex-math><![CDATA[ξ_2c=0,946 ;ξ_3c=0,8]]></tex-math></inline-formula></p>
      <p id="_paragraph-31">Based on the values ​​determined above, we determine the threshold value of the linear slippage rate according to the formula (5a).</p>
      <p id="paragraph-3f6c5576b3726a187f0ed8d33281a170">
        <inline-formula id="inline-formula-b8d1698e1a666d7349752db035733781" content-type="math/tex">
          <tex-math><![CDATA[C^* (t,t_0 )=[1/(E_b (t_0))]-[1/(E_b (t) )]+C(∞,28)Ω(t_0 )f(t-t_0 )=]]></tex-math>
        </inline-formula>
      </p>
      <p id="paragraph-d909fb2e7fad1a0294b34fe84ef2e0ab">
        <inline-formula id="inline-formula-560ddc203d59e64fc5cc74fa6906eb5d" content-type="math/tex">
          <tex-math><![CDATA[=C^* (∞,60)=[1/(3,387∙10^10 )]-[1/(3,569∙10^10 )]+5,979∙10^(-11)∙0,841∙1,0=0,518m^2/H]]></tex-math>
        </inline-formula>
      </p>
      <p id="_paragraph-33">[ ] We determine the parameters of the nonlinear function from table 10.</p>
      <p id="paragraph-7f8f1de3ad51a791f4596ce328d8ba17">
        <inline-formula id="inline-formula-8e1a5f9e15d01f1e12b2bfd77b303ce5" content-type="math/tex">
          <tex-math><![CDATA[V_k=1,3;    V_c=1,6.]]></tex-math>
        </inline-formula>
      </p>
      <p id="_paragraph-35">We determine the modulus of continuous deformation according to the following formula.</p>
      <p id="paragraph-08d1452a2850f9add71f7e6978849011">
        <inline-formula id="inline-formula-cbbb1612e7f4e94071759cadadf414b9" content-type="math/tex">
          <tex-math><![CDATA[E_b^f (∞,60)={(1+V_k)/(E_b (∞))+(1+V_e ) C^* (∞,60)}^(-1)=]]></tex-math>
        </inline-formula>
      </p>
      <p id="paragraph-aaf7c86352ea3620ccdd4181e60078c6">
        <inline-formula id="inline-formula-6c421e14e54d7c5fa01697e1419dd0ea" content-type="math/tex">
          <tex-math><![CDATA[=[(1+1,3)/(3,569∙10^10 )+(1+1,6)0,518∙10^(-10) ]^(-1)=0,502∙10^10 H/m^2]]></tex-math>
        </inline-formula>
      </p>
      <p id="_paragraph-36">(25) from the table. <inline-formula id="inline-formula-6e4d7aab61a10bb413dd5d74037ee4cc" content-type="math/tex"><tex-math><![CDATA[f_0=0,13]]></tex-math></inline-formula></p>
      <p id="_paragraph-37">Using the following formula, we determine the effective deformation modulus of the compressive part of the column concrete [5].</p>
      <p id="_paragraph-38">The limit height of the compression zone on the transverse section of a reinforced concrete column operating in non-central compression is determined using the following formulas.</p>
      <fig id="figure-panel-7ee06ea5201cc3bf302c145063e0abf2">
        <label>Figure 8</label>
        <caption>
          <p id="paragraph-8093c0e9375d2b3895afa868987f3218" />
        </caption>
        <graphic id="graphic-761ab8c98bb15f0763770bd580067175" mimetype="image" mime-subtype="jpeg" xlink:href="r4.jpg" />
      </fig>
      <p id="_paragraph-39">here is the calculated compressive strength of concrete <inline-formula id="inline-formula-0bef184edf57cb842055c814dbc0e0eb" content-type="math/tex"><tex-math><![CDATA[R_b (28);]]></tex-math></inline-formula></p>
      <p id="paragraph-77965522c2698925f8a2e53a47bc0166">
        <inline-formula id="inline-formula-7589de830b34bd65aeb87fedf8240f4d" content-type="math/tex">
          <tex-math><![CDATA[R_b (28)=(R_bn (28))/γ_bc =(22∙10^6)/1,3=17∙10^6 H/m^2]]></tex-math>
        </inline-formula>
      </p>
      <p id="_paragraph-40">here <inline-formula id="inline-formula-bfe1858c099de54b26a5a6d8dec1e305" content-type="math/tex"><tex-math><![CDATA[R_bn=22∙10^6  ,γ_bc=1,3.]]></tex-math></inline-formula></p>
      <p id="_paragraph-41">In the matter under consideration 𝜉= 0.645 &gt; 𝜉R = 0,345 the height of the compressive part of the column cross-section surface is selected according to the values ​​determined by the following formula [6].</p>
      <fig id="figure-panel-7bb6c7166b54487d8d377d43dc444f68">
        <label>Figure 9</label>
        <caption>
          <p id="paragraph-4045bbb3265ebf9b4b1a4309215b66e0" />
        </caption>
        <graphic id="graphic-440470e6ed9a56ea424e7beffb5cbbdd" mimetype="image" mime-subtype="jpeg" xlink:href="r5.jpg" />
      </fig>
      <p id="_paragraph-46">From the solution of this quadratic equation, we determine the following value.</p>
      <p id="_paragraph-47">
        <inline-formula id="inline-formula-725feb50bf6a9f21ca18a5bcd9deae9c" content-type="math/tex">
          <tex-math><![CDATA[x_min (∞,60)=[1/2A] √(B^2+4AC)-B=]]></tex-math>
        </inline-formula>
      </p>
      <p id="paragraph-78b20c2f65fc635292aa29e09b1654d5">
        <inline-formula id="inline-formula-a3b8121e5467845df523fe0829dc0df3" content-type="math/tex">
          <tex-math><![CDATA[=[1/(2∙3,61∙10^6 )] √((1,898∙10^5 )^2+4∙3,61∙10^6∙8,505∙10^3 )-1,898∙10^5=]]></tex-math>
        </inline-formula>
      </p>
      <p id="paragraph-8358f5eb204de41e052fa80143ad6946">
        <inline-formula id="inline-formula-b2a7a5eb440d1d6d22ee85abb4e1e80f" content-type="math/tex">
          <tex-math><![CDATA[=0,0289 m = 2,89 sm.]]></tex-math>
        </inline-formula>
      </p>
      <p id="_paragraph-48"><inline-formula id="inline-formula-5623543b11345629a7e48627fc311eae" content-type="math/tex"><tex-math><![CDATA[q_0 (∞,60)  ]]></tex-math></inline-formula> We determine its value according to the following equation.</p>
      <fig id="figure-panel-18a07c803ca47ff7ac1bf20fcebaf5f5">
        <label>Figure 10</label>
        <caption>
          <p id="paragraph-7c56facca0023932d99c4ae1bd900170" />
        </caption>
        <graphic id="graphic-560dbfa31ba139f0b4201d662a306492" mimetype="image" mime-subtype="jpeg" xlink:href="r6.jpg" />
      </fig>
      <p id="_paragraph-51">the coefficients are assumed to be values. We determine the stiffness of a reinforced concrete column operating in non-central compression according to the limit stress state in the following order [7].</p>
      <p id="_paragraph-52"><inline-formula id="inline-formula-696f81ba578c0558cb87e712debd28ae" content-type="math/tex"><tex-math><![CDATA[x_(min,e) (∞,60)  ]]></tex-math></inline-formula> we calculate the limit value of the bending moment generated in a reinforced concrete column operating in non-central compression, based on the height of the compression part of the cross-sectional surface [8].</p>
      <fig id="figure-panel-2c0cdf5308ad70626eadf9a615c4a025">
        <label>Figure 11</label>
        <caption>
          <p id="paragraph-5ac83a2292c4535ab6ce9f100d800d44" />
        </caption>
        <graphic id="graphic-f1fb548e00508423ae9aeb10cf009f0f" mimetype="image" mime-subtype="jpeg" xlink:href="r7.jpg" />
      </fig>
      <p id="_paragraph-58">The height of the compressive part of the cross-sectional surface of the column</p>
      <p id="paragraph-845a197f3efef2f71bf73cf8e18d1d95">
        <inline-formula id="inline-formula-9ea7b826081ee658a6e3a9dc18179bbe" content-type="math/tex">
          <tex-math><![CDATA[x_min (∞,60) ]]></tex-math>
        </inline-formula>
      </p>
      <fig id="figure-panel-de1aaaa06305f638142d8f4dd35f4ec1">
        <label>Figure 12</label>
        <caption>
          <p id="paragraph-b8542fc6723c7a943a389a98763d0de3" />
        </caption>
        <graphic id="graphic-d95e3afc06ccc381f6c7a9489401fd4e" mimetype="image" mime-subtype="jpeg" xlink:href="r8.jpg" />
      </fig>
      <p id="_paragraph-61">We define the root of the initial equation as follows.</p>
      <p id="paragraph-0e42abde9173c80765f1f97917532fdd">
        <inline-formula id="inline-formula-f82c06b6691333276bb24deef035f50b" content-type="math/tex">
          <tex-math><![CDATA[x_(min,e) (∞,60)=[1/2A](√(B^2+4AC)-B)=[1/(2∙1,695∙10^6 )]∙]]></tex-math>
        </inline-formula>
      </p>
      <p id="paragraph-995e7f275a2876c84161fa181f7680a8">
        <inline-formula id="inline-formula-f1f1e6ed8cf0d83655f3eb3f155e2e9d" content-type="math/tex">
          <tex-math><![CDATA[∙(√((0,144∙10^6 )^2+4∙1,695∙10^6∙2,59∙10^4 )-0,144∙10^6 )=0,088 m]]></tex-math>
        </inline-formula>
      </p>
      <p id="_paragraph-62">We check the condition of the problem as follows.</p>
      <fig id="figure-panel-e3444d1a6cd4a34246ffd7fe92ff3455">
        <label>Figure 13</label>
        <caption>
          <p id="paragraph-8a57d58b427bea8dc0f7a11b415b7142" />
        </caption>
        <graphic id="graphic-72d7f08f061ef66a4583ea2449252cc6" mimetype="image" mime-subtype="jpeg" xlink:href="r9.jpg" />
      </fig>
      <p id="_paragraph-64">And so, [9]</p>
      <p id="paragraph-77369850f94e55a49af9662000053c8c">
        <inline-formula id="inline-formula-6812a73a976921a35ec13f9043824321" content-type="math/tex">
          <tex-math><![CDATA[1,695∙10^6 〖∙x〗_(min,e)^3 (∞,60)+0,144∙10^6∙x_(min,e)^2 (∞,60)+ +86,428∙10^3∙x_(min,e) (∞,60)-9,399∙10^3=0]]></tex-math>
        </inline-formula>
      </p>
      <p id="_paragraph-65">or after contraction</p>
      <p id="paragraph-f066c53efcfd49c2389085b2de28f3ac">
        <inline-formula id="inline-formula-8e9ae5277a84b599da8c610a42113094" content-type="math/tex">
          <tex-math><![CDATA[1695∙x_(min,e)^3 (∞,60)+144∙x_(min,e)^2 (∞,60)+86,428∙x_(min,e) (∞,60)-9,399=0]]></tex-math>
        </inline-formula>
      </p>
      <p id="_paragraph-66">Let's solve this equation according to Newton's method [10].</p>
      <p id="_paragraph-67">
        <inline-formula id="inline-formula-928e6537e5474360026a24c362b1be36" content-type="math/tex">
          <tex-math><![CDATA[x_(min,e)^n (∞,60)=x_(min,e)^(n-1) (∞,60)-{F[x_(min,e)^(n-1) (∞,60)]/F'[x_(min,e)^(n-1) (∞,60)] },]]></tex-math>
        </inline-formula>
      </p>
      <p id="_paragraph-68">here</p>
      <fig id="figure-panel-b71d68eb19f78de02eaf79e3f3dafa5e">
        <label>Figure 14</label>
        <caption>
          <p id="paragraph-455554e868d540f8ec5cca63149230eb" />
        </caption>
        <graphic id="graphic-c952a50235a9147aafb5cfeb436fa38f" mimetype="image" mime-subtype="jpeg" xlink:href="r10.jpg" />
      </fig>
      <p id="_paragraph-69">We choose the following parameters as initial values.</p>
      <fig id="figure-panel-0eb14347688e3998bb16aac36ed10184">
        <label>Figure 15</label>
        <caption>
          <p id="paragraph-be49ab8eefbb92b9d950043a1db73c97" />
        </caption>
        <graphic id="graphic-910e009e949736404b3c0a70e7656aa8" mimetype="image" mime-subtype="jpeg" xlink:href="r11.jpg" />
      </fig>
      <p id="_paragraph-70">and the value is equal to the first approximation <inline-formula id="inline-formula-459b2f00d41c1ffcf2b5669dadacb25f" content-type="math/tex"><tex-math><![CDATA[x_(min,e) (∞,60)]]></tex-math></inline-formula></p>
      <p id="paragraph-18a871d1bc07d3dd5ee673f1cdec615f">
        <inline-formula id="inline-formula-5a59204d3bebdca54c69b1ca7871225d" content-type="math/tex">
          <tex-math><![CDATA[x_(min,e)^((1))=(0,0839-(-0,133))/146,39=0,0848 m]]></tex-math>
        </inline-formula>
      </p>
      <p id="_paragraph-71"><inline-formula id="inline-formula-7141e2b93daa3130bde60a53118f9e53" content-type="math/tex"><tex-math><![CDATA[x_(min,e) (∞,60)]]></tex-math></inline-formula> The second approximation value of is determined as follows.</p>
      <p id="paragraph-ad7dadae632229255b2b5b0a55732c3f">
        <inline-formula id="inline-formula-d88ad61b166a29c9526e5d301a437149" content-type="math/tex">
          <tex-math><![CDATA[F(x_(min,e)^((1)) )=1695∙〖0,0848〗^3+144∙〖0,0848〗^2+86,428∙0,0848-9,399= -7,486∙10^(-4);]]></tex-math>
        </inline-formula>
      </p>
      <p id="paragraph-2b15237b71bef877abb4ade0b37a6dde">
        <inline-formula id="inline-formula-676abda4b62ddc44ccaaeabdbdf6f1a2" content-type="math/tex">
          <tex-math><![CDATA[F(x_(min,e)^((1)) )=3∙1695∙〖0,0848〗^2+2∙144∙0,0848+86,428=147,42;]]></tex-math>
        </inline-formula>
      </p>
      <p id="paragraph-b028fb65bdd558c51d9495468f2f007c">
        <inline-formula id="inline-formula-6382d70833b018d1cc815b12ce1f8df8" content-type="math/tex">
          <tex-math><![CDATA[x_(min,e)^((2))=(0,0848-(-7,846∙10^(-4)))/147,42=0,0848]]></tex-math>
        </inline-formula>
      </p>
      <p id="_paragraph-72">We take the value of the height of the compression zone of the cross-sectional area of ​​the column determined by the double approximation as follows [11].</p>
      <p id="paragraph-d803fbeac7fa4a6f1b5bcaa774bc4afc">
        <inline-formula id="inline-formula-0fcfddfb73b440bc7c6126ac0a14f894" content-type="math/tex">
          <tex-math><![CDATA[x_(min,e) (∞,60)=0,0848 m]]></tex-math>
        </inline-formula>
      </p>
      <p id="_paragraph-73">Now, we determine the stresses produced in compression and tension reinforcements using the following formulas:</p>
      <fig id="figure-panel-e1777761948a49773e997a54a4c81b89">
        <label>Figure 16</label>
        <caption>
          <p id="paragraph-54359d5e8b58d28a022a0f790b0570dd" />
        </caption>
        <graphic id="graphic-34c1c7ae93af176e48bd37b645f38a88" mimetype="image" mime-subtype="jpeg" xlink:href="r12.jpg" />
      </fig>
      <p id="_paragraph-75">We accept the following values ​​for the account.</p>
      <fig id="figure-panel-1db1d031ef221a06eaad9f04b58351cc">
        <label>Figure 17</label>
        <caption>
          <p id="paragraph-53d9b0b1a5289c3e061b434137844227" />
        </caption>
        <graphic id="graphic-ca9690c6417814e5158f04d85fc37f5b" mimetype="image" mime-subtype="jpeg" xlink:href="r13.jpg" />
      </fig>
      <p id="_paragraph-76">The limiting value of the bending moment generated in a reinforced concrete column operating in eccentric compression [12].</p>
      <p id="paragraph-a77d664b615706b9c21414319c8a8609">Now let's determine the continuous critical force according to the following equation.</p>
      <fig id="figure-panel-8226c5e049a13ba3878cd1d99cb6fd42">
        <label>Figure 18</label>
        <caption>
          <p id="paragraph-d1da17cf86b9619a1c3847941c75a5eb" />
        </caption>
        <graphic id="graphic-955b5c60a78a7f3cec9283276f9880dd" mimetype="image" mime-subtype="jpeg" xlink:href="r14.jpg" />
      </fig>
    </sec>
    <sec id="heading-c4cd4d7c16f82e5a6abcc8498802f364">
      <title>
        <bold id="_bold-17">Conclusion</bold>
      </title>
      <p id="paragraph-2167243ae3e8a0cd803cfd09829782fc">As a result of longitudinal bending of reinforced concrete columns operating in eccentric compression, the value of the initial bending moment increases. Therefore, the load-bearing capacity of the column decreases, and the slip property of the concrete increases. In this case, the strength of the column is calculated according to its deformed state. The priority of the column depends on the critical amount of permanent load placed on it.</p>
    </sec>
  </body>
  <back />
</article>